Parse an expression
An arithmetical expression consists of 2 numbers and an operator between them, for instance:
1 + 2
1.2 * 3.4
-3 / -6
-2 - 2
The operator is one of:
There may be extra spaces at the beginning, at the end or between the parts.
Create a function
parse(expr) that takes an expression and returns an array of 3 items:
- The first number.
- The operator.
- The second number.
let [a, op, b] = parse("1.2 * 3.4"); alert(a); // 1.2 alert(op); // * alert(b); // 3.4
A regexp for a number is:
-?\d+(\.\d+)?. We created it in previous tasks.
An operator is
- Here the dash
-goes first in the brackets, because in the middle it would mean a character range, while we just want a character
- A slash
/.../, we’ll do that later.
We need a number, an operator, and then another number. And optional spaces between them.
The full regular expression:
To get a result as an array let’s put parentheses around the data that we need: numbers and the operator:
The result includes:
result == "1.2 + 12"(full match)
result == "1.2"(first group
(-?\d+(\.\d+)?)– the first number, including the decimal part)
result == ".2"(second group
(\.\d+)?– the first decimal part)
result == "+"(third group
([-+*\/])– the operator)
result == "12"(forth group
(-?\d+(\.\d+)?)– the second number)
result == undefined(fifth group
(\.\d+)?– the last decimal part is absent, so it’s undefined)
We only want the numbers and the operator, without the full match or the decimal parts.
The full match (the arrays first item) can be removed by shifting the array
The decimal groups can be removed by making them into non-capturing groups, by adding
?: to the beginning:
The final solution: